Home Topics Previous next


DEVELOPING CIRCUIT EQUATIONS

INTRODUCTION
EXAMPLE 1
EXAMPLE 2
EXAMPLE 3
SUMMARY


INTRODUCTION

In this page, equations that describe the behaviour of some circuits are formed. Once you have formed the equations, you can calculate the coefficients based on the component values and then select the interactive page for the type of input to the circuit. In that page, you can key-in the coefficients. You can then obtain the solution step by step or see the solution.

Go to Top of the Page


EXAMPLE 1

Fig27

For the in Fig. 27, equations that describe its behaviour are developed.

DIFFERENTIAL EQUATION APPROACH

For the circuit in Fig. 27, the differential equation is obtained as shown below.

ole00

For this circuit, the initial conditions required are stated below.

ole01

LAPLACE TRANSFORM APPROACH

We can obtain a Laplace transform function for the inductor current as follows. The transformed circuit is shown in Fig. 28.

Fig28

ole02

Equations (1.6), (1.7) and (1.8) are self-explanatory.

ole03

Replace VC(s) in equation (1.7) by the expression for VC(s) in equation (1.8). Then you get equation (1.9). Re-arrange equation (1.9) and get equation (1.10).

ole04

Equation (1.11) presents the inductor current as a Laplace transform function. You can derive equation (1.11) from equations (1.4) and (1.5).

STATE VARIABLE APPROACH

ole05

The state-equation, expressed by equation (1.14) can be expressed in terms of Laplace transforms.

ole06

We can get the following equation from equation (1.15).

ole07

Hence we get the Laplace transform function for the inductor current, as shown below.

ole08

It is the same function, obtained earlier.

Go to Top of the Page


EXAMPLE 2

Fig. 29

Obtain the circuit equations for the circuit in Fig. 29.

Solution:

Differential Equations Approach

From the circuit in Fig. 29, we can obtain the following equations. The process is a bit tedious.

ole09

From equation (2.4), we can obtain a Laplace transform function for current i2(t).

ole10

Laplace Transforms Approach

Fig. 30

From the transformed circuit in Fig. 30, we can obtain the following equation.

ole11

Equations (2.5) and (2.6) appear to be different. They are the same if equation is (2.7) is true.

ole12

It is seen that equations (2.5) and (2.6) are equal to each other.

State variableApproach

From the circuit in Fig. 29, we can obtain the following equations. It is relatively easy to form the state equation.

ole13

We can express the above equation in terms of Laplace transforms.

ole14

After simplification, we get the following equation.

ole15

Go to Top of the Page


EXAMPLE 3

Fig. 31

Obtain the circuit equations for the circuit in Fig. 31.

Solution:

Differential Equations Approach

From the circuit in Fig. 31, we can obtain the following equations.

ole16

Replace iL in equation (3.1) by the expression in equation (3.3).

ole17

Laplace Transforms Approach

Fig. 32

From the transformed circuit in Fig. 32, we can obtain the following equations.

ole18

Re-arrange equation (3.5).

ole19

It is quite tedious to obtain equation (3.6). We can verify whether we get the same expression, starting from the differential equation. From equation (3.4), we get that

ole20

It can be seen that equations (3.6) and (3.7) are equal to each other, as shown below.

ole21

State variableApproach

From the circuit in Fig. 31, we can obtain the following equations.

ole22

We can get the second equation as follows.

ole23

The state equation can then be obtained.

ole24

Go to Top of the Page


SUMMARY

The examples have shown that it is tedious to deal with symbolic functions. Given numerical values, it is relatively easy to get the circuit equations. Hence only some examples are shown to illustrate the process of obtaining circuit equations in terms of symbols. Given any circuit, the process is similar. The next page presents an interactive example of a second-order circuit with a step input.

Go to Top of the Page


Home Topics Previous next